Drag Racing Technique Improve your track times

Elevation Questions

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Old Jul 27, 2005 | 06:03 AM
  #1  
92PurpleHaze's Avatar
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Joined: Dec 2004
Posts: 87
From: Huntington WV
Elevation Questions

Hey guys, I have been looking around alot at peoples ET's.. I have noticed that elevation plays a pretty substantial role in you ET.. My local track is in Hurricane WV .. I was just wondering how I could go about finding out what the elevation is there, and after I find out, how do I get my "real" ET.. is there some kind of mathmatical equation for this?? I have seen alot of people put there time and also say its been "corrected".. Just trying to understand all this stuff..

Thanks in advance
Old Jul 27, 2005 | 08:07 AM
  #2  
DarkHorse's Avatar
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Joined: Jul 2002
Posts: 1,433
From: Akron, Ohio
Re: Elevation Questions

Elevation plays a part as well as weather. What track do you race at? Sometimes you can google the track and the word elevation and get some hits that will show the elevation of the track. Then use a website that archives their weather days so that you can correct your times. Times are corrected to sea level.

For instance - my best ever time of 12.360@110.82 would correct to:


Based on:
Temp: 64°
Humidity: 21%
Track Altitude: 700 feet
Pressure: 30.48 in.


Density Altitude = 613 feet ET MPH
Uncorrected 12.360 @ 110.82
Corrected 12.28 @ 111.52
Old Jul 27, 2005 | 09:20 PM
  #3  
Stephen 87 IROC's Avatar
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Joined: Mar 2000
Posts: 2,037
From: 51°N 114°W, 3500' elevation
Re: Elevation Questions

It took a bit to figure out what track you're talking about.

Kanawha Valley Dragway Park offical altitude is 560 feet. Not a lot compared to higher altitude tracks but with poor weather conditions, you could easily be 2000 - 3000 feet density altitude.

http://www.kanrace.com/
Old Jul 28, 2005 | 08:29 AM
  #4  
Injuneer's Avatar
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Joined: Nov 1998
Posts: 71,122
From: Hell was full so they sent me to NJ
Re: Elevation Questions

The NHRA altitude correction charts don't even go down below 1,600-ft.

http://www.nhra.com/tech_specs/altitude.html

Using the formulas they use for "stock" class vehicles, for a 560-ft elevation, the correction factors would be:

ET X 0.9957
MPH X 1.039

In other words, a 13.50@105 mph at 560-ft would convert to 13.44@105.4

Interestingly, the NHRA formulas are based on 230.77-ft for ET, and 278.57-ft for MPH, at least that's what you get if you back calculate the numbers they show in the chart.
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