i have always heard this if you have a passenger in your car for every 100lbs he is, that will cost you 1 car length for each 100 lbs.
is this true.... anyone know?
-Mike
is this true.... anyone know?
-Mike
Registered User
Ditto on the .1 off of your quarter mile time. That's about all I've ever gained or seen anyone gain when dropping weight, it's not precise but it's a good reference.
Registered User
Quote:
Originally posted by 97BBlackZ
Im not sure about that but i heard for every 100 lb its like .1 sec off your 1/4 time...
...and the distance in .1 sec would depend on how fast you were going. Originally posted by 97BBlackZ
Im not sure about that but i heard for every 100 lb its like .1 sec off your 1/4 time...

but also... think how much more sluggish your car feels w/ a 200lb friends of yours in it.
Administrator
If you take a 3650# car that runs 100MPH, and add 100# to it, you will add 0.12-seconds to the ET. At 100MPH, that is 17.6-feet. A 4th Gen is about 16.3-ft long, so it looks like a good "rule-of-thumb".
If the same car was pulling 120MPH trap speeds, the length difference becomes 21.1-ft, so its more like 1.3 car lengths.
If the same car was pulling 120MPH trap speeds, the length difference becomes 21.1-ft, so its more like 1.3 car lengths.
well that is good to know..... i had a feeling it was around that from what i have heard.
thanks for the input
Mike
thanks for the input
Mike