Is it true that 100lbs equals a full car length in racing?

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Jul 7, 2003 | 10:52 AM
  #1  
i have always heard this if you have a passenger in your car for every 100lbs he is, that will cost you 1 car length for each 100 lbs.

is this true.... anyone know?


-Mike
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Jul 7, 2003 | 10:57 AM
  #2  
Im not sure about that but i heard for every 100 lb its like .1 sec off your 1/4 time...
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Jul 7, 2003 | 11:04 AM
  #3  
Ditto on the .1 off of your quarter mile time. That's about all I've ever gained or seen anyone gain when dropping weight, it's not precise but it's a good reference.
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Jul 7, 2003 | 11:05 AM
  #4  
Quote:
Originally posted by 97BBlackZ
Im not sure about that but i heard for every 100 lb its like .1 sec off your 1/4 time...
...and the distance in .1 sec would depend on how fast you were going.
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Jul 7, 2003 | 11:16 AM
  #5  
but also... think how much more sluggish your car feels w/ a 200lb friends of yours in it.
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Jul 7, 2003 | 11:57 AM
  #6  
If you take a 3650# car that runs 100MPH, and add 100# to it, you will add 0.12-seconds to the ET. At 100MPH, that is 17.6-feet. A 4th Gen is about 16.3-ft long, so it looks like a good "rule-of-thumb".

If the same car was pulling 120MPH trap speeds, the length difference becomes 21.1-ft, so its more like 1.3 car lengths.
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Jul 7, 2003 | 02:27 PM
  #7  
well that is good to know..... i had a feeling it was around that from what i have heard.


thanks for the input


Mike
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