383 bored .040 over ?
What's the new CID and liters?
Thx-Goose

 

I believe a .40 over bore with a 3.75 stroke would be 385 Cubic Inches.

Thx,
Claude

 

It has 6" rods, if that helps.

 

The longer rod will not effect Cubic Inches but will give more torque..You will still end up with 385 CI with a .040 overbore and a 3.75 inch crank.

Thx,
Claude

 

Simple ratio will give you the answer....solve for x......Im not gonna do all the work for ya

5.7\350 = x\385

 

Cool, man. That should help.

 

Thoes teachers were right, Math is inportant.

 

Yep. Everything you need to know.
Sometimes using 61 cu.in. = 1 Liter is convenient.

Example: 4.04 * 4.04 * 8 * .7854 = 384.57 cu. in.

384.57 cu. in /61 = 6.30 L

 

just to clarify, by bore im' sure he means radius

area of circle times length or depth :0

4.04'' = diamter
2.2'' = radiuis

area = pi R^2

so 3.14 *2.02

multiply by stroke

so 3.14 *2.02 *3.75

multiply by number of clyinders

3.14 *2.02* 3.73 * 8

TADA!

 

I don't think so, .7854 is Pi/4.

Your formula is also correct though

 

woops, made the mistake of just spotting the bore *bore and assuming it meant radius ^2

I didn't realize you went through all the trouble of simplifying

I was never one for memorizing that stuff. i just memorize fundimentals and derive from there.

I cant believe the way people memorize trig identites

Sin^2 + cos^2 = 1 will get you them all; how people havn't noticed this is beyond me

 

I'm thinking I shouldn't have cut math class so much now!

 

How can Oldsstroker, miss the stroke. Your one number short!

Or, D^2 * h * N * .7854 = X cu. in. /61.024 = X liters

Are we having fun yet!!!

 

so what is the answer?