Today I'm getting my 18 inch Tubolares with 275/35/18 Kumhos mounted on my TA, and of course garaging the stock 16 inch 5 spoke rim.

How much heavier are my new rims going to be compared to my old? I was only jsut thinking of this when I was lugging around my new rims.

Thanks,

Leo

 

Get out the ole bathroom scale and see

 

I was tempted to do that but I don't think we have one here

 

Well we are gonna have to figure out a way to weigh them unless you can get the shipping weight and find a weight faq for stock wheels

 

The actual weight is not much different,what will slow your car down is ineartia which it the ditribution of mass around the axis of rotation ineartia is mass times radius squared, the radius is the major factor so your going from 8" to 9" so 64 to 81 times the mass difference. but all these numbers are small compared to your cars acceleration. torque equals rotational acceleration x ineatia. Take your tires cicumference and use a 14 sec 1/4 mile as example and figure out the angular acceleration of your tire in radians/sec. if your tire is 24" this is 30 rads/sec2. Lets assume your stocker is 45# and the 18 is 55#. inertia for stock is 0.62 vs 0.96. so your torque loss will be the differnce of the torque equations. so 28.8 - 18.6 = 10.2 Ft# will be your torque loss per tire, approximitly which is really addtional load creted by the larger mass when you run a 1/4 mile. This probably won'tbe the case though because your new wheels are probably dsigned well enough that they weigh less than the stock ones.

 

Sweet mother of god what kind of scientist/mathmetician are you?!?!?

nice answer!

 

Ahh, I'm just goofing around, seems resonable though, doesn't it?

A 3600#car doing a 14 sec 1/4 mile will require a constant appllied force at the wheels of 10.31 ft/sec2 X 3600/32.2 = 1,153# (F=MA), you got like 3.5 axle gears so you would need 330 ft# engine. not including wind drag. I'm just a college student, i can't explain why a dyno chart shows 300/ whatever ft# torque when like I said you need a force of 1153#, it would take a few hours to completly figure it out and match the numbers in both directions and figure out the reltionships and what's really happening.