If an LT-1 Camaro puts out 325 lbs/ft of torque at 2200 rpm, does that mean the torque delivered to the stock rear axle in 2nd gear (autocross) at 2200 rpm =
325 lbs/ft X 1.78(2nd)X 3.42 = 1978.47 lbs/ft of torque assuming (for the sake of argument) no drivetrain losses?

And if that's true, does each wheel see 1900+ lbs/ft or is it divided between the wheels for 950+ lbs/ft each wheel?? Then, does the limited-slip play with the total amount? Trying to clarify something i read about limited-slip diffs. thanks!

 

You've correctly calculated the torque delivered to the rear axle, assuming no drivetrain losses. You could always refine that further by multiplying by 0.86 for a manual trans and 0.82 for the A4.

The torque, in a perfect world is split evenly between the two wheels..... 990 ft-lb of reaction developed at each end of the axle. With a stock 25.6" tire diameter, that translates to a force of 927# from each of the wheels against the pavement. If the axle is not slipping, I would think the split would be roughly 50/50, less some unequal reactions taken out bending the torque around the corner through the pinion to the ring. I'd have to think about that.

As soon as the wheels start to experience differential movement, the limited slip should lock the axles effectively together. So, similar torque/forces at each wheel.

Obviously its not a perfect world, and the analysis is greatly oversimplified. Without the limited slip, it is conceivable that the difference at each wheel would be greater, because the traction at each wheel will be different, based on the cornering direction and the fact that the body reacts to the torque in the driveshaft by lifting on one side and being forced down on the other. Once you lock the axles together with the limited slip, it would seem to provide a "more equal" distribution of forces, at least the thrust at each tire propelling th chassis forward.

Have you asked this question on the Auto-X board? They probably know the real answer, rather than my theoretical babbling... .

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Fred
94 Formula A3+1: 381/TH400+OD/N2O

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[This message has been edited by Injuneer 94FormM6 (edited August 14, 2002).]

 

Thanks!

 

Also do not forget TQ mutiplication for the TQ Converter(Hence the name) If you have an Automatic

Mine is 2.7 at Full stall(3,800-4,000) near my tq peak

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Ellis
Team Captain
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