383 Stroker .030 over is 6.3liter, so what's a... - CamaroZ28.Com Message Board


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Old 10-15-2003, 08:59 AM   #1
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383 Stroker .030 over is 6.3liter, so what's a...

383 bored .040 over ?
What's the new CID and liters?
Thx-Goose
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Old 10-15-2003, 09:01 AM   #2
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I believe a .40 over bore with a 3.75 stroke would be 385 Cubic Inches.

Thx,
Claude
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Old 10-15-2003, 09:07 AM   #3
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It has 6" rods, if that helps.
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Old 10-15-2003, 09:16 AM   #4
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The longer rod will not effect Cubic Inches but will give more torque..You will still end up with 385 CI with a .040 overbore and a 3.75 inch crank.

Thx,
Claude
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Old 10-15-2003, 09:22 AM   #5
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Simple ratio will give you the answer....solve for x......Im not gonna do all the work for ya

5.7\350 = x\385
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Old 10-15-2003, 09:34 AM   #6
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Quote:
Originally posted by gb95zconv
Simple ratio will give you the answer....solve for x......Im not gonna do all the work for ya

5.7\350 = x\385
Cool, man. That should help.
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Old 10-15-2003, 10:19 AM   #7
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Thoes teachers were right, Math is inportant.
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Old 10-15-2003, 05:34 PM   #8
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Quote:
Originally posted by Slow95car
bore * bore * stroke * 8 * .7854

.061cid = 1 cc = 1ml
Yep. Everything you need to know.
Sometimes using 61 cu.in. = 1 Liter is convenient.

Example: 4.04 * 4.04 * 8 * .7854 = 384.57 cu. in.

384.57 cu. in /61 = 6.30 L
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Old 10-15-2003, 05:51 PM   #9
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Quote:
Originally posted by Slow95car
bore * bore * stroke * 8 * .7854

.061cid = 1 cc = 1ml
just to clarify, by bore im' sure he means radius

area of circle times length or depth :0

4.04'' = diamter
2.2'' = radiuis

area = pi R^2

so 3.14 *2.02

multiply by stroke

so 3.14 *2.02 *3.75

multiply by number of clyinders

3.14 *2.02* 3.73 * 8

TADA!
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Old 10-15-2003, 05:57 PM   #10
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Quote:
Originally posted by TreySpeed
just to clarify, by bore im' sure he means radius

I don't think so, .7854 is Pi/4.

Your formula is also correct though
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Old 10-15-2003, 06:10 PM   #11
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Quote:
Originally posted by 94formulabz
I don't think so, .7854 is Pi/4.

Your formula is also correct though
woops, made the mistake of just spotting the bore *bore and assuming it meant radius ^2

I didn't realize you went through all the trouble of simplifying

I was never one for memorizing that stuff. i just memorize fundimentals and derive from there.

I cant believe the way people memorize trig identites

Sin^2 + cos^2 = 1 will get you them all; how people havn't noticed this is beyond me
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Old 10-15-2003, 06:22 PM   #12
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I'm thinking I shouldn't have cut math class so much now!
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Old 10-16-2003, 12:57 PM   #13
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Quote:
Example: 4.04 * 4.04 * 8 * .7854 = 384.57 cu. in.
How can Oldsstroker, miss the stroke. Your one number short!

Or, D^2 * h * N * .7854 = X cu. in. /61.024 = X liters

Are we having fun yet!!!
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Old 10-16-2003, 02:12 PM   #14
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so what is the answer?
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