Who would win: 03 Cobra or 05 Vette?
Re: Who would win: 03 Cobra or 05 Vette?
Originally Posted by nuke61
If you have enough track to truly reach top speed, however, lightness becomes irrelevant. Light weight only helps acceleration."
Re: Who would win: 03 Cobra or 05 Vette?
Originally Posted by Big Red Jim
You're right, it'd be minor. Dare I say irrelevant? I think I already did. And we're back to square one. Thanks.
Re: Who would win: 03 Cobra or 05 Vette?
Originally Posted by Bob Cosby
You're welcome - though whether or not it is "irrelevant" is rather debatable. Please see previous comment dealing with assumptions, presumptions, and guessing.
Originally Posted by nuke61
The following primarily discusses the aerodynamic forces, which are a square function, but briefly discusses the power required to overcome those forces, which are a cube function. Note that weight is not a part of any of the equations. For all practical purposes, it's simply not a factor.
http://snipurl.com/cx1x
http://snipurl.com/cx1x
Re: Who would win: 03 Cobra or 05 Vette?
Originally Posted by Big Red Jim
Nuke did my dirty work. No guesswork involved here. Consider yourself educated now.
Honestly, I have little interest in the topic at hand, but decided to respond to a comment I still believe to be inaccurate - despite my education, or lack their of.
Re: Who would win: 03 Cobra or 05 Vette?
So now you've been provided facts to back up a statement I made, and you still think it's inaccurate.
I believe the moon is indeed made of cheese. I don't care what facts you throw at me.
Your lack of interest in this topic is made clear by the number of replies you've made in this thread. Is it too much to ask to admit when you're wrong? Or does your hat size prevent that?
I believe the moon is indeed made of cheese. I don't care what facts you throw at me.
Your lack of interest in this topic is made clear by the number of replies you've made in this thread. Is it too much to ask to admit when you're wrong? Or does your hat size prevent that?
Last edited by Big Red Jim; Feb 20, 2005 at 12:43 PM.
Re: Who would win: 03 Cobra or 05 Vette?
Originally Posted by Big Red Jim
So now you've been provided facts to back up a statement I made, and you still think it's inaccurate.
I believe the moon is indeed made of cheese. I don't care what facts you throw at me.
Your lack of interest in this topic is made clear by the number of replies you've made in this thread.
Is it too much to ask to admit when you're wrong?
Or does your hat size prevent that?
Know what I mean?
Re: Who would win: 03 Cobra or 05 Vette?
Originally Posted by Bob Cosby
I believe your assertion that - and I quote: "Weight is irrelevant for top speed" - is inaccurate.
Re: Who would win: 03 Cobra or 05 Vette?
Originally Posted by Bob Cosby
Ok. Define "reasonable." Or consider me silly and misguided. I have no issues either way. 

What's the aerodynamic force, ignoring rolling resistance, required to move a Vette through the air at 200 mph? About 450 lbs, while the rolling resistance for a car with DOUBLE the weight is only about a 40 lb difference in force required. Insignificant.
http://snipurl.com/cx23
So, concerning a 3000 Vette vs. a 6000 lb Vette, the difference in top speed is insignificant, therefore, a weight doubling is insignificant when discussing top speed and street cars.
A doubling of weight, as improbable as that may be, is reasonable. Asking if a 30,000 lb Vette would have the same top speed as a 3,000 lb Vette, other factors being equal, is not reasonable.
Re: Who would win: 03 Cobra or 05 Vette?
Ok. So help me out here. Everything else being equal (power, gearing, aerodynamics), what would be the top speed difference (in MPH, please) of a car weighing 3000 vs one weighing 3900 lbs. Pick whatever power and drag you wish.
Thanks.
Thanks.
Re: Who would win: 03 Cobra or 05 Vette?
Roll resistance power (approximate) = weight * 0.013 * mph / 375
Air drag resistance power (approximate) = fA * Cd * 0.003 * mph^3 / 375
Car A weighs 3000 lbs
Car B weighs 3900 lbs
3000 lbs * 0.013 * 200 mph / 375 = 20.8 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 / 375 = 384 lbs force to overcome air resistance
Or 404.8 lbs total force
3900 lbs * 0.013 * 200 mph / 375 = 27.04 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 /375 = 384 lbs force to overcome air resistance
Or 411.04 lbs total force
That's approximately 1% more power required for the 3900 lb car vs. the 3000 lb car, shown by 411/405=1.015. Since speed is proportional to the cube root of power, the cube root of 1 is 1. In other words, speed will decrease by about 1%, or 2 mph.
Bottom line is that the 3000 lb car will go 200 mph, the 3900 lb car will go 198 mph, all other factors being equal. You may disagree, but I call a 1% difference in top speed insiginificant.
BTW, I know you didn't ask for it, but comparing a 6000 lb car vs. a 3000 lb car...
6000 lbs * 0.013 * 200 mph / 375 = 41.6 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 / 375 = 384 lbs force to overcome air resistance
Or 425.6 lbs total force, or about 5% more power. Again using the speed vs. power proportion, speed will decrease about 1.7%, or 3.4 mph. In other words, a car that weighs twice as much as another car, if all other factors are equal (gearing, horsepower, wheels, etc.) the light car will do 200 mph and twice as heavy car will do 196.6 mph.
Air drag resistance power (approximate) = fA * Cd * 0.003 * mph^3 / 375
Car A weighs 3000 lbs
Car B weighs 3900 lbs
3000 lbs * 0.013 * 200 mph / 375 = 20.8 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 / 375 = 384 lbs force to overcome air resistance
Or 404.8 lbs total force
3900 lbs * 0.013 * 200 mph / 375 = 27.04 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 /375 = 384 lbs force to overcome air resistance
Or 411.04 lbs total force
That's approximately 1% more power required for the 3900 lb car vs. the 3000 lb car, shown by 411/405=1.015. Since speed is proportional to the cube root of power, the cube root of 1 is 1. In other words, speed will decrease by about 1%, or 2 mph.
Bottom line is that the 3000 lb car will go 200 mph, the 3900 lb car will go 198 mph, all other factors being equal. You may disagree, but I call a 1% difference in top speed insiginificant.
BTW, I know you didn't ask for it, but comparing a 6000 lb car vs. a 3000 lb car...
6000 lbs * 0.013 * 200 mph / 375 = 41.6 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 / 375 = 384 lbs force to overcome air resistance
Or 425.6 lbs total force, or about 5% more power. Again using the speed vs. power proportion, speed will decrease about 1.7%, or 3.4 mph. In other words, a car that weighs twice as much as another car, if all other factors are equal (gearing, horsepower, wheels, etc.) the light car will do 200 mph and twice as heavy car will do 196.6 mph.
Last edited by nuke61; Feb 20, 2005 at 03:32 PM.
Re: Who would win: 03 Cobra or 05 Vette?
Originally Posted by nuke61
You're quite incorrect. First of all, "ergonomics" has absolutely NOTHING to do with top speed. You apparently have no idea what ergonomics even means. Look it up. Lastly, weight has little to no effect on top speed. Weight affects accleration rate, but not top speed.
The friction from the air is so enormous compared to other forces (remember, it's a cube function) that the minor increase in wheel and bearing friction due to weight increase is negligible. If you think otherwise, you simply have no clue about the physics involved.
The friction from the air is so enormous compared to other forces (remember, it's a cube function) that the minor increase in wheel and bearing friction due to weight increase is negligible. If you think otherwise, you simply have no clue about the physics involved.
Re: Who would win: 03 Cobra or 05 Vette?
Originally Posted by nuke61
Roll resistance power (approximate) = weight * 0.013 * mph / 375
Air drag resistance power (approximate) = fA * Cd * 0.003 * mph^3 / 375
Car A weighs 3000 lbs
Car B weighs 3900 lbs
3000 lbs * 0.013 * 200 mph / 375 = 20.8 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 / 375 = 384 lbs force to overcome air resistance
Or 404.8 lbs total force
3900 lbs * 0.013 * 200 mph / 375 = 27.04 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 /375 = 384 lbs force to overcome air resistance
Or 411.04 lbs total force
That's approximately 1% more power required for the 3900 lb car vs. the 3000 lb car, shown by 411/405=1.015. Since speed is proportional to the cube root of power, the cube root of 1 is 1. In other words, speed will decrease by about 1%, or 2 mph.
Bottom line is that the 3000 lb car will go 200 mph, the 3900 lb car will go 198 mph, all other factors being equal. You may disagree, but I call a 1% difference in top speed insiginificant.
BTW, I know you didn't ask for it, but comparing a 6000 lb car vs. a 3000 lb car...
6000 lbs * 0.013 * 200 mph / 375 = 41.6 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 / 375 = 384 lbs force to overcome air resistance
Or 425.6 lbs total force, or about 5% more power. Again using the speed vs. power proportion, speed will decrease about 1.7%, or 3.4 mph. In other words, a car that weighs twice as much as another car, if all other factors are equal (gearing, horsepower, wheels, etc.) the light car will do 200 mph and twice as heavy car will do 196.6 mph.
Air drag resistance power (approximate) = fA * Cd * 0.003 * mph^3 / 375
Car A weighs 3000 lbs
Car B weighs 3900 lbs
3000 lbs * 0.013 * 200 mph / 375 = 20.8 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 / 375 = 384 lbs force to overcome air resistance
Or 404.8 lbs total force
3900 lbs * 0.013 * 200 mph / 375 = 27.04 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 /375 = 384 lbs force to overcome air resistance
Or 411.04 lbs total force
That's approximately 1% more power required for the 3900 lb car vs. the 3000 lb car, shown by 411/405=1.015. Since speed is proportional to the cube root of power, the cube root of 1 is 1. In other words, speed will decrease by about 1%, or 2 mph.
Bottom line is that the 3000 lb car will go 200 mph, the 3900 lb car will go 198 mph, all other factors being equal. You may disagree, but I call a 1% difference in top speed insiginificant.
BTW, I know you didn't ask for it, but comparing a 6000 lb car vs. a 3000 lb car...
6000 lbs * 0.013 * 200 mph / 375 = 41.6 lbs force to overcome roll resistance
20 sq ft * 0.30 * 0.003 * 200^3 / 375 = 384 lbs force to overcome air resistance
Or 425.6 lbs total force, or about 5% more power. Again using the speed vs. power proportion, speed will decrease about 1.7%, or 3.4 mph. In other words, a car that weighs twice as much as another car, if all other factors are equal (gearing, horsepower, wheels, etc.) the light car will do 200 mph and twice as heavy car will do 196.6 mph.
Thanks.
Re: Who would win: 03 Cobra or 05 Vette?
Originally Posted by Bob Cosby
So I suppose that my earlier statement.... was safe and correct.


Originally Posted by Big Red Jim
Like I said, you are fighting wind resistance more than weight when you get up around the 200mph mark.


