Not sure this is advanced, but.......

Granted 53cc stock LT1 chambers, how much does milling heads .020" reduce the size? TIA!

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The Toy
The Commuter
"Real men drive opposite lock."

 

30 thousandths?

Or...

Anyone want to give us the pole instead of the fish and post the formula .


Ryan

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Slow and Broke

 

I dont think there is a formula for this. The combustion chamber is sort of an irregular shape and calculating its volume would getnasty real quick. Plus you would need a different formula for each type of combustion chamber (open chamber, closed, hemi, etc). I'm quite certain it's just easier to get out a graduated cylinder and measure it

Anyways back to the original question. As a "rule of thumb" AFR says flat milling reduces volume by 1 cc for every .006" taken off. So .020" would knock 3.33cc's (.020/.006) of one of their heads. For angle milling its one cc per .008". Stock LT1 heads would probably be pretty close.

That said those are just general guidelines, to get you in the ballpark. The only way you'll really know the volume is to measure them once you're done.

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Jason
93 TA, M6

 

1cc for every .006"? Thank you sir - that's a big help. Just need to plug it into the CR formula now

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The Toy
The Commuter
"Real men drive opposite lock."

 

If my math is correct, overall swept volume, gasket volume, deck height volume, and piston volume remaining equal, milling the heads .020 should increase compression about .25 points. Thanks again for the info.

 

Makes sense. Thanks man!

Ryan