Understanding flow characteristics

Rodrigues
07-22-2004, 10:18 PM
I have an intercooler with the spearco 2-230 cores http://www.turboneticsinc.com/liquid.html, which spearco rates to 1500cfm. Now lets say I get a T88, which flows aprox 1700cfm... what happens? Seems like a lot of people are getting away with tiny intercoolers... heres a pic of mine.


http://kak.com/camaro/intercooler/DSCN0741.JPG
http://kak.com/camaro/intercooler/DSCN0740.JPG

engineermike
07-22-2004, 10:45 PM
The intercooler will explode since there is nowhere for the extra 200 cfm to go. :) Just kidding.

I'm not sure if they're rating it based on restriction or cooling capacity. Either way, that's way bigger than the Vortech Aftercooler and people run 9's with that.

Mike

Rodrigues
07-22-2004, 11:30 PM
Think its possible to push over 1,200 at the crank through an intercooler like this?

The intercooler will explode since there is nowhere for the extra 200 cfm to go. :) Just kidding.

I'm not sure if they're rating it based on restriction or cooling capacity. Either way, that's way bigger than the Vortech Aftercooler and people run 9's with that.

Mike

JordonMusser
07-22-2004, 11:36 PM
1500cfm is measured at a pressure drop (1.5 psi i believe). so if you try to flow more through it, you will get a greater pressure drop. 1500cfm is a nice size IC.

Rodrigues
07-22-2004, 11:44 PM
Is the pressure drop usually pretty linear vs initial boost?

engineermike
07-22-2004, 11:52 PM
Pressure drop is proportional to the square of flow. So, if you plan on flowing a TRUE 1700 cfm, then you could find the pressure drop by:

dP = 1.5 * (1700/1500)^2 = 1.93 psi

Rodrigues
07-23-2004, 12:53 AM
According to the graphs of the t88 its able to push a peak of 120 lb min, so 120/.069= 1739 peak. Now lets assume a 2 psi drop. So the more pressure i push through, a larger percent is being lost to pressure drop. So even if I push exactly 1500cfm, im still losing 1.5 psi.... not too shabby only losing a half psi or so for 200 more cfm imo.
Pressure drop is proportional to the square of flow. So, if you plan on flowing a TRUE 1700 cfm, then you could find the pressure drop by:

dP = 1.5 * (1700/1500)^2 = 1.93 psi